The mole: from atoms on a scale to counted particles
Chemistry counts by weighing, and the mole is the bridge. One mole is exactly 6.022 × 10²³ entities (Avogadro's number, Nₐ), just as a dozen always means twelve. The reason it works is that molar mass, in grams per mole (g/mol), numerically equals the atomic or formula mass in unified atomic mass units: carbon is 12.011 u, so one mole of carbon weighs 12.011 g and contains 6.022 × 10²³ carbon atoms.
That equality lets three conversions run in both directions:
- g → mol: divide the mass by the molar mass (n = m/M).
- mol → particles: multiply by Avogadro's number (N = n × Nₐ).
- mol → volume of gas: at standard conditions one mole of an ideal gas occupies about 22.4 L at 0 °C and 1 atm (24.5 L at 25 °C and 1 atm — know which standard your problem assumes).
Example of the chain: 18.0 g of water (M = 18.02 g/mol) is 1.00 mol, which is 6.022 × 10²³ molecules, made of 3.011 × 10²³ hydrogen atoms and 1.506 × 10²³ oxygen atoms. The percentages that follow from the formula are percent composition: water is 11.19% H by mass and 88.81% O.
The same logic runs backwards from data to formula. Empirical formulas are the smallest whole-number ratio of atoms, found from mass (or percent) compositions by converting each percentage to grams, dividing by molar masses, then dividing by the smallest result. Molecular formulas are whole-number multiples of empirical formulas — the multiple comes from comparing the compound's measured molar mass with the empirical mass. Combustion analysis works exactly this way: carbon ends up as CO₂ and hydrogen as H₂O, and the masses of those products fix the C:H ratio.